What are the solutions to the equation 4b^2-4b+7=6 ?

The solutions to the equation 4b^2-4b+7=6 are b= 1/2

Find the zeros of 4b^2-4b+7=6

The zeros of 4b^2-4b+7=6 are b= 1/2

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4 b^{2} - 4 b + 7 = 6

b = \frac{1}{2}

Decimal Notation

b = 0.5

Solution steps

4 b^{2} - 4 b + 7 = 6

Move

6

to the left side

4 b^{2} - 4 b + 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

b_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

b = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

b = \frac{1}{2}

The solution to the quadratic equation is:

b = \frac{1}{2}

3 a^{2} + a^{3} b^{2} - 5 a^{2} b

\frac{6 ^{6}}{6 ^{3}}

\frac{Q}{12} = 32

5 x^{2} + 10 x - 75

2 \frac{π}{\frac{π}{2}}

What are the solutions to the equation 4b^2-4b+7=6 ?
The solutions to the equation 4b^2-4b+7=6 are b= 1/2
Find the zeros of 4b^2-4b+7=6
The zeros of 4b^2-4b+7=6 are b= 1/2