What is ((2-x)(2x+1)^2)/((x-4)^4)<= 0 ?

The solution to ((2-x)(2x+1)^2)/((x-4)^4) 4

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((2-x)(2x+1)^2)/((x-4)^4)<= 0

\frac{( 2 - x ) ( 2 x + 1 ) ^{2}}{( x - 4 ) ^{4}} \leq 0

x = - \frac{1}{2} or 2 \leq x < 4 or x > 4

Interval Notation

x = - \frac{1}{2} \cup [2, 4) \cup (4, \infty)

Decimal Notation

x = - 0.5 or 2 \leq x < 4 or x > 4

Solution steps

\frac{( 2 - x ) ( 2 x + 1 ) ^{2}}{( x - 4 ) ^{4}} \leq 0

Identify the intervals

x = - \frac{1}{2} or 2 \leq x < 4 or x > 4

3 u^{2} + 10 u + 7

\frac{k + 5}{k ^{2} - 7 k + 10} + \frac{5 k}{5 k ^{2}}

(8 + 10)^{2}

5 x - x = 44

- 30 u = 9 u^{2} + 25

What is ((2-x)(2x+1)^2)/((x-4)^4)<= 0 ?
The solution to ((2-x)(2x+1)^2)/((x-4)^4)<= 0 is x=-1/2 \lor 2<= x<4\lor x>4