What are the solutions to the equation n^2-6n-3=0 ?

The solutions to the equation n^2-6n-3=0 are n=3+2sqrt(3),n=3-2sqrt(3)

Find the zeros of n^2-6n-3=0

The zeros of n^2-6n-3=0 are n=3+2sqrt(3),n=3-2sqrt(3)

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n^{2} - 6 n - 3 = 0

n = 3 + 23, n = 3 - 23

Decimal

n = 6.46410 \dots, n = - 0.46410 \dots

Solution steps

n^{2} - 6 n - 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 3) = 43

n_{1, 2} = \frac{- ( - 6 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 6 ) + 4 3}{2 \cdot 1}, n_{2} = \frac{- ( - 6 ) - 4 3}{2 \cdot 1}

n = \frac{- ( - 6 ) + 4 3}{2 \cdot 1} : 3 + 23

n = \frac{- ( - 6 ) - 4 3}{2 \cdot 1} : 3 - 23

The solutions to the quadratic equation are:

n = 3 + 23, n = 3 - 23

0.5 s + 1 = 7 + 4.5 s

(a + 3)^{2} = 25

20 x^{2} - 3 x - 9

\frac{x + 2}{3} = 5

\frac{35}{7}

What are the solutions to the equation n^2-6n-3=0 ?
The solutions to the equation n^2-6n-3=0 are n=3+2sqrt(3),n=3-2sqrt(3)
Find the zeros of n^2-6n-3=0
The zeros of n^2-6n-3=0 are n=3+2sqrt(3),n=3-2sqrt(3)