What are the solutions to the equation w^2-30w-7=0 ?

The solutions to the equation w^2-30w-7=0 are w=15+2sqrt(58),w=15-2sqrt(58)

Find the zeros of w^2-30w-7=0

The zeros of w^2-30w-7=0 are w=15+2sqrt(58),w=15-2sqrt(58)

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w^{2} - 30 w - 7 = 0

w = 15 + 258, w = 15 - 258

Decimal

w = 30.23154 \dots, w = - 0.23154 \dots

Solution steps

w^{2} - 30 w - 7 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 30)^{2} - 4 \cdot 1 \cdot (- 7) = 458

w_{1, 2} = \frac{- ( - 30 ) \pm 4 58}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 30 ) + 4 58}{2 \cdot 1}, w_{2} = \frac{- ( - 30 ) - 4 58}{2 \cdot 1}

w = \frac{- ( - 30 ) + 4 58}{2 \cdot 1} : 15 + 258

w = \frac{- ( - 30 ) - 4 58}{2 \cdot 1} : 15 - 258

The solutions to the quadratic equation are:

w = 15 + 258, w = 15 - 258

\frac{3}{5} (r + 10) = 12

2 x^{3} \cdot 2 x^{2}

f (a) = \frac{8 a ^{3} - 10 a}{20 a ^{3} - 25 a}

2 (2 x^{2} - 3 x) \geq - 9

(\frac{3 x ^{4}}{y ^{6}})^{5}

What are the solutions to the equation w^2-30w-7=0 ?
The solutions to the equation w^2-30w-7=0 are w=15+2sqrt(58),w=15-2sqrt(58)
Find the zeros of w^2-30w-7=0
The zeros of w^2-30w-7=0 are w=15+2sqrt(58),w=15-2sqrt(58)