What is factor 3x^{-4}+6x^{-5}+12x^{-6} ?

The solution to factor 3x^{-4}+6x^{-5}+12x^{-6} is (3(x^2+2x+4))/(x^6)

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factor 3x^{-4}+6x^{-5}+12x^{-6}

factor

3 x^{- 4} + 6 x^{- 5} + 12 x^{- 6}

\frac{3 ( x ^{2} + 2 x + 4 )}{x ^{6}}

Solution steps

3 x^{- 4} + 6 x^{- 5} + 12 x^{- 6}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{- 4} = x^{- 6} x^{2}, x^{- 5} = x^{- 6} x

= 3 x^{- 6} x^{2} + 6 x^{- 6} x + 12 x^{- 6}

Rewrite as

= 3 x^{- 6} x^{2} + 2 \cdot 3 x^{- 6} x + 4 \cdot 3 x^{- 6}

Factor out common term

3 x^{- 6}

= 3 x^{- 6} (x^{2} + 2 x + 4)

Refine

= \frac{3 ( x ^{2} + 2 x + 4 )}{x ^{6}}

\frac{2 ^{- 3}}{3 ^{- 2}}

\frac{1}{2} (x + 1) - \frac{1}{3} (2 x + 1) > \frac{1}{3} (x - 1)

\frac{1 - \frac{5}{13}}{2}

98 k

7 t - 18 = - 116

What is factor 3x^{-4}+6x^{-5}+12x^{-6} ?
The solution to factor 3x^{-4}+6x^{-5}+12x^{-6} is (3(x^2+2x+4))/(x^6)