What are the solutions to the equation 2(x+4)^2=18 ?

The solutions to the equation 2(x+4)^2=18 are x=-1,x=-7

Find the zeros of 2(x+4)^2=18

The zeros of 2(x+4)^2=18 are x=-1,x=-7

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2 (x + 4)^{2} = 18

x = - 1, x = - 7

Solution steps

2 (x + 4)^{2} = 18

Divide both sides by

2

(x + 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 9 : x = - 1

Solve

x + 4 = - 9 : x = - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

x^{2} = - 4 x - 6

\frac{2}{3} \cdot \frac{1}{2}

9 b^{2} - 9 = 279

x^{2} + 5 x - 63 = 3 x

t = - 0.07089 \cdot 0^{\frac{3}{2}} + 0.07089

What are the solutions to the equation 2(x+4)^2=18 ?
The solutions to the equation 2(x+4)^2=18 are x=-1,x=-7
Find the zeros of 2(x+4)^2=18
The zeros of 2(x+4)^2=18 are x=-1,x=-7