What are the solutions to the equation 2y^2-17y=-35 ?

The solutions to the equation 2y^2-17y=-35 are y=5,y= 7/2

Find the zeros of 2y^2-17y=-35

The zeros of 2y^2-17y=-35 are y=5,y= 7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 y^{2} - 17 y = - 35

y = 5, y = \frac{7}{2}

Decimal Notation

y = 5, y = 3.5

Solution steps

2 y^{2} - 17 y = - 35

Move

35

to the left side

2 y^{2} - 17 y + 35 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 35}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 35 = 3

y_{1, 2} = \frac{- ( - 17 ) \pm 3}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 17 ) + 3}{2 \cdot 2}, y_{2} = \frac{- ( - 17 ) - 3}{2 \cdot 2}

y = \frac{- ( - 17 ) + 3}{2 \cdot 2} : 5

y = \frac{- ( - 17 ) - 3}{2 \cdot 2} : \frac{7}{2}

The solutions to the quadratic equation are:

y = 5, y = \frac{7}{2}

a^{7} + b^{7}

\frac{0.682 - 0.48}{0.02212}

\frac{3}{x ^{2}} - \frac{x}{2 y}

0.7 5^{5}

4 x - 5 = - 5

What are the solutions to the equation 2y^2-17y=-35 ?
The solutions to the equation 2y^2-17y=-35 are y=5,y= 7/2
Find the zeros of 2y^2-17y=-35
The zeros of 2y^2-17y=-35 are y=5,y= 7/2