What are the solutions to the equation (z+3)^2=5 ?

The solutions to the equation (z+3)^2=5 are z=sqrt(5)-3,z=-sqrt(5)-3

Find the zeros of (z+3)^2=5

The zeros of (z+3)^2=5 are z=sqrt(5)-3,z=-sqrt(5)-3

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(z + 3)^{2} = 5

z = 5 - 3, z = - 5 - 3

Decimal Notation

z = - 0.76393 \dots, z = - 5.23606 \dots

Solution steps

(z + 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 3 = 5 : z = 5 - 3

Solve

z + 3 = - 5 : z = - 5 - 3

The solutions to the quadratic equation are:

z = 5 - 3, z = - 5 - 3

\frac{1}{2} (2)^{- 1}

∣ 8 x - 5 ∣ \leq 11

i \cdot \frac{1}{i}

(3^{2})^{- 2}

\frac{x + 2}{2} = \frac{x + 7}{2}

What are the solutions to the equation (z+3)^2=5 ?
The solutions to the equation (z+3)^2=5 are z=sqrt(5)-3,z=-sqrt(5)-3
Find the zeros of (z+3)^2=5
The zeros of (z+3)^2=5 are z=sqrt(5)-3,z=-sqrt(5)-3