What is -2x^2-x+1>= 0 ?

The solution to -2x^2-x+1>= 0 is -1<= x<= 1/2

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-2x^2-x+1>= 0

- 2 x^{2} - x + 1 \geq 0

- 1 \leq x \leq \frac{1}{2}

Interval Notation

[- 1, \frac{1}{2}]

Decimal Notation

- 1 \leq x \leq 0.5

Solution steps

- 2 x^{2} - x + 1 \geq 0

Factor

- 2 x^{2} - x + 1 : - (2 x - 1) (x + 1)

- (2 x - 1) (x + 1) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (2 x - 1) (x + 1)) (- 1) \leq 0 \cdot (- 1)

Simplify

(2 x - 1) (x + 1) \leq 0

Identify the intervals

- 1 \leq x \leq \frac{1}{2}

\frac{1}{2 + 3 i}

(x^{\frac{- 1}{3}})^{2}

17 \cdot \frac{25}{100}

\frac{z}{6} < 15