What are the solutions to the equation k^2+2k=0 ?

The solutions to the equation k^2+2k=0 are k=0,k=-2

Find the zeros of k^2+2k=0

The zeros of k^2+2k=0 are k=0,k=-2

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k^{2} + 2 k = 0

k = 0, k = - 2

Solution steps

k^{2} + 2 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

k_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 2 + 2}{2 \cdot 1}, k_{2} = \frac{- 2 - 2}{2 \cdot 1}

k = \frac{- 2 + 2}{2 \cdot 1} : 0

k = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

k = 0, k = - 2

x^{3} - 12 x^{2} + 36 x

x^{2} + 5 x - 5 x - 25

3 x - 6 = 0

0. 7^{5}

\frac{2 ^{3}}{2 ^{- 1}}

What are the solutions to the equation k^2+2k=0 ?
The solutions to the equation k^2+2k=0 are k=0,k=-2
Find the zeros of k^2+2k=0
The zeros of k^2+2k=0 are k=0,k=-2