What are the solutions to the equation 2c^2+c=6 ?

The solutions to the equation 2c^2+c=6 are c= 3/2 ,c=-2

Find the zeros of 2c^2+c=6

The zeros of 2c^2+c=6 are c= 3/2 ,c=-2

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2 c^{2} + c = 6

c = \frac{3}{2}, c = - 2

Solution steps

2 c^{2} + c = 6

Move

6

to the left side

2 c^{2} + c - 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 6) = 7

c_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 2}

Separate the solutions

c_{1} = \frac{- 1 + 7}{2 \cdot 2}, c_{2} = \frac{- 1 - 7}{2 \cdot 2}

c = \frac{- 1 + 7}{2 \cdot 2} : \frac{3}{2}

c = \frac{- 1 - 7}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

c = \frac{3}{2}, c = - 2

- \frac{1}{2} x = 4

5 (- 2 k - 3) + 2 k

- ∣ 6 c ∣ - 2 > - 10

1^{- \frac{2}{3}}

8 x - 15 > x^{2}

What are the solutions to the equation 2c^2+c=6 ?
The solutions to the equation 2c^2+c=6 are c= 3/2 ,c=-2
Find the zeros of 2c^2+c=6
The zeros of 2c^2+c=6 are c= 3/2 ,c=-2