What are the solutions to the equation -16t^2+96t+256=0 ?

The solutions to the equation -16t^2+96t+256=0 are t=-2,t=8

Find the zeros of -16t^2+96t+256=0

The zeros of -16t^2+96t+256=0 are t=-2,t=8

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- 16 t^{2} + 96 t + 256 = 0

t = - 2, t = 8

Solution steps

- 16 t^{2} + 96 t + 256 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 256}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 256 = 160

t_{1, 2} = \frac{- 96 \pm 160}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 160}{2 ( - 16 )}, t_{2} = \frac{- 96 - 160}{2 ( - 16 )}

t = \frac{- 96 + 160}{2 ( - 16 )} : - 2

t = \frac{- 96 - 160}{2 ( - 16 )} : 8

The solutions to the quadratic equation are:

t = - 2, t = 8

(1 + 2 i) (1 - 4 i)

\frac{5}{6} + \frac{3}{8}

m^{4} \cdot 2 m^{- 3}

9 a^{4} + 3 a^{3} - 21 a

2 x^{2} + 5 x \leq 25

What are the solutions to the equation -16t^2+96t+256=0 ?
The solutions to the equation -16t^2+96t+256=0 are t=-2,t=8
Find the zeros of -16t^2+96t+256=0
The zeros of -16t^2+96t+256=0 are t=-2,t=8