What are the solutions to the equation 0=x^2+12x+36 ?

The solutions to the equation 0=x^2+12x+36 are x=-6

Find the zeros of 0=x^2+12x+36

The zeros of 0=x^2+12x+36 are x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + 12 x + 36

x = - 6

Solution steps

0 = x^{2} + 12 x + 36

Switch sides

x^{2} + 12 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 36 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 1}

x = \frac{- 12}{2 \cdot 1}

\frac{- 12}{2 \cdot 1} = - 6

x = - 6

The solution to the quadratic equation is:

x = - 6

x^{2} = 8 x - 21

\frac{x - 1}{2} = \frac{x + 3}{3}

10 m + 3 (n - 8) - 7 (m - 12) + 9 n

30 \cdot 20

2 \leq 20

What are the solutions to the equation 0=x^2+12x+36 ?
The solutions to the equation 0=x^2+12x+36 are x=-6
Find the zeros of 0=x^2+12x+36
The zeros of 0=x^2+12x+36 are x=-6