What is factor p^4+3p^3-8p-24 ?

The solution to factor p^4+3p^3-8p-24 is (p+3)(p-2)(p^2+2p+4)

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factor p^4+3p^3-8p-24

factor

p^{4} + 3 p^{3} - 8 p - 24

(p + 3) (p - 2) (p^{2} + 2 p + 4)

Solution steps

p^{4} + 3 p^{3} - 8 p - 24

= (p^{4} + 3 p^{3}) + (- 8 p - 24)

Factor out

p^{3}

from

p^{4} + 3 p^{3} : p^{3} (p + 3)

Factor out

- 8

from

- 8 p - 24 : - 8 (p + 3)

= p^{3} (p + 3) - 8 (p + 3)

Factor out common term

p + 3

= (p + 3) (p^{3} - 8)

Factor

p^{3} - 8 : (p - 2) (p^{2} + 2 p + 2^{2})

= (p + 3) (p - 2) (p^{2} + 2 p + 2^{2})

2^{2} = 4

= (p + 3) (p - 2) (p^{2} + 2 p + 4)

10 x^{2} + 9 x - 9

3^{7} \cdot 3^{- 4}

2 x^{2} - 21 x + 49

\frac{2 a ^{3} b ^{- 4}}{3 a ^{5} b ^{- 2}}

\frac{3.999}{3.999 - 4}

What is factor p^4+3p^3-8p-24 ?
The solution to factor p^4+3p^3-8p-24 is (p+3)(p-2)(p^2+2p+4)