What is 1+(5x)/7-1/5 (x+7)>= x ?

The solution to 1+(5x)/7-1/5 (x+7)>= x is x<=-14/17

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1+(5x)/7-1/5 (x+7)>= x

1 + \frac{5 x}{7} - \frac{1}{5} (x + 7) \geq x

x \leq - \frac{14}{17}

Interval Notation

(- \infty, - \frac{14}{17}]

Decimal Notation

x \leq - 0.82352 \dots

Solution steps

1 + \frac{5 x}{7} - \frac{1}{5} (x + 7) \geq x

Move

1

to the right side

\frac{5 x}{7} - \frac{1}{5} (x + 7) \geq x - 1

Multiply by LCM

25 x - 7 (x + 7) \geq 35 x - 35

Expand

- 7 (x + 7) : - 7 x - 49

25 x - 7 x - 49 \geq 35 x - 35

Add similar elements:

25 x - 7 x = 18 x

18 x - 49 \geq 35 x - 35

Move

49

to the right side

18 x \geq 35 x + 14

Move

35 x

to the left side

- 17 x \geq 14

Multiply both sides by

- 1

17 x \leq - 14

Divide both sides by

17

x \leq - \frac{14}{17}

25 x - 17 x = - 64

1792

5 x - 9 = 11 x + 15

(5 y + 2) (y - 3) = - 13 (2 + y)

x^{3} y^{3}

What is 1+(5x)/7-1/5 (x+7)>= x ?
The solution to 1+(5x)/7-1/5 (x+7)>= x is x<=-14/17