What is (6ab^3c^4)(-3a^2b^3c) ?

The solution to (6ab^3c^4)(-3a^2b^3c) is -18a^3b^6c^5

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simplify (6ab^3c^4)(-3a^2b^3c)

simplify

(6 a b^{3} c^{4}) (- 3 a^{2} b^{3} c)

- 18 a^{3} b^{6} c^{5}

Solution steps

(6 a b^{3} c^{4}) (- 3 a^{2} b^{3} c)

Apply rule:

a (- b) = - ab

(6 a b^{3} c^{4}) (- 3 a^{2} b^{3} c) = - 6 a b^{3} c^{4} \cdot 3 a^{2} b^{3} c

= - 6 a b^{3} c^{4} \cdot 3 a^{2} b^{3} c

Multiply the numbers:

- 6 \cdot 3 = - 18

= - 18 a b^{3} c^{4} a^{2} b^{3} c

Simplify

a a^{2} : a^{3}

= - 18 a^{3} b^{3} c^{4} b^{3} c

Simplify

b^{3} b^{3} : b^{6}

= - 18 a^{3} b^{6} c^{4} c

Simplify

c^{4} c : c^{5}

= - 18 a^{3} b^{6} c^{5}

- 39 x = 702

1 + 4 x + 6 x^{2} + 4 x^{3} + x^{4}

\frac{4}{5} n + 2 = \frac{2}{5} n - 4

\frac{3 x + 3}{4 x - 1} - \frac{9}{2 x - 3} \leq 0

15 n^{2} + n - 2

What is (6ab^3c^4)(-3a^2b^3c) ?
The solution to (6ab^3c^4)(-3a^2b^3c) is -18a^3b^6c^5