What are the solutions to the equation 9x^2-27x+20=0 ?

The solutions to the equation 9x^2-27x+20=0 are x= 5/3 ,x= 4/3

Find the zeros of 9x^2-27x+20=0

The zeros of 9x^2-27x+20=0 are x= 5/3 ,x= 4/3

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9 x^{2} - 27 x + 20 = 0

x = \frac{5}{3}, x = \frac{4}{3}

Decimal Notation

x = 1.66666 \dots, x = 1.33333 \dots

Solution steps

9 x^{2} - 27 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 9 \cdot 20}{2 \cdot 9}

(- 27)^{2} - 4 \cdot 9 \cdot 20 = 3

x_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 3}{2 \cdot 9}, x_{2} = \frac{- ( - 27 ) - 3}{2 \cdot 9}

x = \frac{- ( - 27 ) + 3}{2 \cdot 9} : \frac{5}{3}

x = \frac{- ( - 27 ) - 3}{2 \cdot 9} : \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = \frac{4}{3}

5 \cdot 1 0^{- 6}

11 n - 14 \leq 5 n + 4

\frac{12 !}{4 ! \cdot 8 !}

x^{3} - 2 x^{2} - 2 x - 3

x^{2} - 34 = 2 x - 10

What are the solutions to the equation 9x^2-27x+20=0 ?
The solutions to the equation 9x^2-27x+20=0 are x= 5/3 ,x= 4/3
Find the zeros of 9x^2-27x+20=0
The zeros of 9x^2-27x+20=0 are x= 5/3 ,x= 4/3