What are the solutions to the equation (x^2+2x+4)=0 ?

The solutions to the equation (x^2+2x+4)=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of (x^2+2x+4)=0

The zeros of (x^2+2x+4)=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

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(x^{2} + 2 x + 4) = 0

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

(x^{2} + 2 x + 4) = 0

Refine

x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

x = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

- x > 3

3 c + 7 c + \frac{c}{4 c}

ln (12) - ln (6)

4 x^{2} (x - 3)^{3} - 6 x (x - 3)^{2} + 4 (x - 3)

- x^{2} - 8 x + 20

What are the solutions to the equation (x^2+2x+4)=0 ?
The solutions to the equation (x^2+2x+4)=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of (x^2+2x+4)=0
The zeros of (x^2+2x+4)=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i