What is ((r^2-q^2)/(fq)}{\frac{f-q)/q} ?

The solution to ((r^2-q^2)/(fq)}{\frac{f-q)/q} is (r^2-q^2)/(f(f-q))

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simplify ((r^2-q^2)/(fq)}{\frac{f-q)/q}

simplify

\frac{\frac{r ^{2} - q ^{2}}{f q}}{\frac{f - q}{q}}

\frac{r ^{2} - q ^{2}}{f ( f - q )}

Solution steps

\frac{\frac{r ^{2} - q ^{2}}{f q}}{\frac{f - q}{q}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( r ^{2} - q ^{2} ) q}{f q ( f - q )}

Cancel the common factor:

q

= \frac{r ^{2} - q ^{2}}{f ( f - q )}

8 (3 X - 2) - 4 (4 X - 3) = 6 (4 - X)

(\frac{2}{2})^{3} (\frac{1}{2})^{- 4}

2 x^{2} + 3 x + 1 = 0

(3 x^{2})^{3}

\frac{x ^{2}}{12} - \frac{4 x}{3} + 5 = 0

What is ((r^2-q^2)/(fq)}{\frac{f-q)/q} ?
The solution to ((r^2-q^2)/(fq)}{\frac{f-q)/q} is (r^2-q^2)/(f(f-q))