What are the solutions to the equation 4x^2-12x-27=0 ?

The solutions to the equation 4x^2-12x-27=0 are x= 9/2 ,x=-3/2

Find the zeros of 4x^2-12x-27=0

The zeros of 4x^2-12x-27=0 are x= 9/2 ,x=-3/2

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4 x^{2} - 12 x - 27 = 0

x = \frac{9}{2}, x = - \frac{3}{2}

Decimal Notation

x = 4.5, x = - 1.5

Solution steps

4 x^{2} - 12 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 27 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 27) = 24

x_{1, 2} = \frac{- ( - 12 ) \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 24}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 24}{2 \cdot 4}

x = \frac{- ( - 12 ) + 24}{2 \cdot 4} : \frac{9}{2}

x = \frac{- ( - 12 ) - 24}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - \frac{3}{2}

2 k^{2} + 13 k + 11

30 x^{2} + 95 x + 50

\frac{1}{16 π} ((8 + 2 π) x - 124 π) = 0

28 z - 16 - 7 z = 12

\frac{3}{5} \cdot 4

What are the solutions to the equation 4x^2-12x-27=0 ?
The solutions to the equation 4x^2-12x-27=0 are x= 9/2 ,x=-3/2
Find the zeros of 4x^2-12x-27=0
The zeros of 4x^2-12x-27=0 are x= 9/2 ,x=-3/2