What are the solutions to the equation y^2=4y ?

The solutions to the equation y^2=4y are y=4,y=0

Find the zeros of y^2=4y

The zeros of y^2=4y are y=4,y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} = 4 y

y = 4, y = 0

Solution steps

y^{2} = 4 y

Move

4 y

to the left side

y^{2} - 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

y = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

y = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 4, y = 0

\frac{x}{5} + 2 x = 16 - x

\frac{3}{\frac{1}{3}}

- 5 x - 7 < 28

x^{3} + 2 x^{2} - 5 x - 10

3 (y - 4) = y - 12

What are the solutions to the equation y^2=4y ?
The solutions to the equation y^2=4y are y=4,y=0
Find the zeros of y^2=4y
The zeros of y^2=4y are y=4,y=0