What are the solutions to the equation 3x(x-3)=7x^2-10x ?

The solutions to the equation 3x(x-3)=7x^2-10x are x=0,x= 1/4

Find the zeros of 3x(x-3)=7x^2-10x

The zeros of 3x(x-3)=7x^2-10x are x=0,x= 1/4

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3 x (x - 3) = 7 x^{2} - 10 x

x = 0, x = \frac{1}{4}

Decimal Notation

x = 0, x = 0.25

Solution steps

3 x (x - 3) = 7 x^{2} - 10 x

Expand

3 x (x - 3) : 3 x^{2} - 9 x

3 x^{2} - 9 x = 7 x^{2} - 10 x

Move

10 x

to the left side

3 x^{2} + x = 7 x^{2}

Move

7 x^{2}

to the left side

- 4 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

1^{2} - 4 (- 4) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 4 )}, x_{2} = \frac{- 1 - 1}{2 ( - 4 )}

x = \frac{- 1 + 1}{2 ( - 4 )} : 0

x = \frac{- 1 - 1}{2 ( - 4 )} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{4}

\frac{6 m ^{4} n ^{7}}{12 m ^{5} n ^{8}}

- 5 < x \leq 2

49 g^{2} - 84 g + 36

\frac{π}{4} (\frac{180}{π})

k^{2} = 0

What are the solutions to the equation 3x(x-3)=7x^2-10x ?
The solutions to the equation 3x(x-3)=7x^2-10x are x=0,x= 1/4
Find the zeros of 3x(x-3)=7x^2-10x
The zeros of 3x(x-3)=7x^2-10x are x=0,x= 1/4