x^2+5x+6>0

Solution

x^{2} + 5 x + 6 > 0

x < - 3 or x > - 2

Interval Notation

(- \infty, - 3) \cup (- 2, \infty)

Solution steps

x^{2} + 5 x + 6 > 0

Factor

x^{2} + 5 x + 6 : (x + 2) (x + 3)

(x + 2) (x + 3) > 0

Identify the intervals

x < - 3 or x > - 2

\frac{- 8 a}{7} \cdot \frac{7}{2 a}

4 x^{2} - 27 x - 5 = - 10 x

20 x^{- \frac{1}{2}} + 9 x^{\frac{1}{2}} + x^{\frac{3}{2}}

x^{2} + 8 x + 1 = 10

\frac{79 + 7 i}{6 - 7 i}