What are the solutions to the equation 2/3 x^2-8/3 x+2=0 ?

The solutions to the equation 2/3 x^2-8/3 x+2=0 are x=3,x=1

Find the zeros of 2/3 x^2-8/3 x+2=0

The zeros of 2/3 x^2-8/3 x+2=0 are x=3,x=1

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\frac{2}{3} x^{2} - \frac{8}{3} x + 2 = 0

x = 3, x = 1

Solution steps

\frac{2}{3} x^{2} - \frac{8}{3} x + 2 = 0

Multiply both sides by

3

2 x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4}{2 \cdot 2} : 3

x = \frac{- ( - 8 ) - 4}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

\frac{4 x - 81}{3 x} = 2 x - 12

\frac{2}{x + 6} > - \frac{3}{x - 3}

3 (x + 2) - 1 = 3 x + 1

x^{2} + (x + 21)^{2} = 5 1^{2}

7 x^{2} = 25

What are the solutions to the equation 2/3 x^2-8/3 x+2=0 ?
The solutions to the equation 2/3 x^2-8/3 x+2=0 are x=3,x=1
Find the zeros of 2/3 x^2-8/3 x+2=0
The zeros of 2/3 x^2-8/3 x+2=0 are x=3,x=1