What are the solutions to the equation (m-3)(m-4)=20 ?

The solutions to the equation (m-3)(m-4)=20 are m=8,m=-1

Find the zeros of (m-3)(m-4)=20

The zeros of (m-3)(m-4)=20 are m=8,m=-1

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(m - 3) (m - 4) = 20

m = 8, m = - 1

Solution steps

(m - 3) (m - 4) = 20

Expand

(m - 3) (m - 4) : m^{2} - 7 m + 12

m^{2} - 7 m + 12 = 20

Move

20

to the left side

m^{2} - 7 m - 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

m_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, m_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

m = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

m = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

m = 8, m = - 1

3 (2 + r) > 15 - 2 r

5!

y^{2} = 3

- 1 - (- 8)

7 \cdot \frac{7}{2}

What are the solutions to the equation (m-3)(m-4)=20 ?
The solutions to the equation (m-3)(m-4)=20 are m=8,m=-1
Find the zeros of (m-3)(m-4)=20
The zeros of (m-3)(m-4)=20 are m=8,m=-1