What is factor (x^2-3x)^2-2(x^2-3x)-8 ?

The solution to factor (x^2-3x)^2-2(x^2-3x)-8 is (x-1)(x-2)(x+1)(x-4)

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factor (x^2-3x)^2-2(x^2-3x)-8

factor

(x^{2} - 3 x)^{2} - 2 (x^{2} - 3 x) - 8

(x - 1) (x - 2) (x + 1) (x - 4)

Solution steps

(x^{2} - 3 x)^{2} - 2 (x^{2} - 3 x) - 8

Break the expression into groups

= ((x^{2} - 3 x)^{2} + 2 (x^{2} - 3 x)) + (- 4 (x^{2} - 3 x) - 8)

Factor out

(x^{2} - 3 x)

from

(x^{2} - 3 x)^{2} + 2 (x^{2} - 3 x) : (x^{2} - 3 x) ((x^{2} - 3 x) + 2)

Factor out

- 4

from

- 4 (x^{2} - 3 x) - 8 : - 4 ((x^{2} - 3 x) + 2)

= (x^{2} - 3 x) ((x^{2} - 3 x) + 2) - 4 ((x^{2} - 3 x) + 2)

Factor out common term

(x^{2} - 3 x) + 2

= ((x^{2} - 3 x) + 2) ((x^{2} - 3 x) - 4)

Refine

= (x^{2} - 3 x + 2) (x^{2} - 3 x - 4)

Factor

(x^{2} - 3 x + 2) (x^{2} - 3 x - 4) : (x - 1) (x - 2) (x + 1) (x - 4)

= (x^{2} - 3 x + 2) (x^{2} - 3 x - 4)

Factor

x^{2} - 3 x + 2 : (x - 1) (x - 2)

= (x - 1) (x - 2) (x^{2} - 3 x - 4)

Factor

x^{2} - 3 x - 4 : (x + 1) (x - 4)

= (x - 1) (x - 2) (x + 1) (x - 4)

54 \leq 23

- 4 t \leq 48

- 2 x + 7 = 15

0.32 \cdot (2800 - 31800)

x^{3} - 2 x^{2} + 16 x - 32

What is factor (x^2-3x)^2-2(x^2-3x)-8 ?
The solution to factor (x^2-3x)^2-2(x^2-3x)-8 is (x-1)(x-2)(x+1)(x-4)