What are the solutions to the equation 4x^2-39=10 ?

The solutions to the equation 4x^2-39=10 are x= 7/2 ,x=-7/2

Find the zeros of 4x^2-39=10

The zeros of 4x^2-39=10 are x= 7/2 ,x=-7/2

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4 x^{2} - 39 = 10

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 3.5, x = - 3.5

Solution steps

4 x^{2} - 39 = 10

Move

39

to the right side

4 x^{2} = 49

Divide both sides by

4

x^{2} = \frac{49}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{49}{4}, x = - \frac{49}{4}

\frac{49}{4} = \frac{7}{2}

- \frac{49}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

48 - \frac{6}{3}

(\frac{3 b}{10 b ^{3}})^{4}

(\frac{2}{3}) - 1

∣ 2 x ∣ > 8

27 - 12 + 48

What are the solutions to the equation 4x^2-39=10 ?
The solutions to the equation 4x^2-39=10 are x= 7/2 ,x=-7/2
Find the zeros of 4x^2-39=10
The zeros of 4x^2-39=10 are x= 7/2 ,x=-7/2