What are the solutions to the equation x^2-3x+10=0 ?

The solutions to the equation x^2-3x+10=0 are x= 3/2+i(sqrt(31))/2 ,x= 3/2-i(sqrt(31))/2

Find the zeros of x^2-3x+10=0

The zeros of x^2-3x+10=0 are x= 3/2+i(sqrt(31))/2 ,x= 3/2-i(sqrt(31))/2

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x^{2} - 3 x + 10 = 0

x = \frac{3}{2} + i \frac{31}{2}, x = \frac{3}{2} - i \frac{31}{2}

Solution steps

x^{2} - 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 10 : 31 i

x_{1, 2} = \frac{- ( - 3 ) \pm 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 31 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 31 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 31 i}{2 \cdot 1} : \frac{3}{2} + i \frac{31}{2}

x = \frac{- ( - 3 ) - 31 i}{2 \cdot 1} : \frac{3}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{31}{2}, x = \frac{3}{2} - i \frac{31}{2}

- 1 \cdot 2

\frac{1}{8} - \frac{3}{4}

65 \cdot \frac{π}{180}

\frac{- 3}{2} - 1

- 10 ∣ - 9 - 8 v ∣ \geq - 90

What are the solutions to the equation x^2-3x+10=0 ?
The solutions to the equation x^2-3x+10=0 are x= 3/2+i(sqrt(31))/2 ,x= 3/2-i(sqrt(31))/2
Find the zeros of x^2-3x+10=0
The zeros of x^2-3x+10=0 are x= 3/2+i(sqrt(31))/2 ,x= 3/2-i(sqrt(31))/2