What are the solutions to the equation 8x^2+20x+8=0 ?

The solutions to the equation 8x^2+20x+8=0 are x=-1/2 ,x=-2

Find the zeros of 8x^2+20x+8=0

The zeros of 8x^2+20x+8=0 are x=-1/2 ,x=-2

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8 x^{2} + 20 x + 8 = 0

x = - \frac{1}{2}, x = - 2

Decimal Notation

x = - 0.5, x = - 2

Solution steps

8 x^{2} + 20 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 8 \cdot 8}{2 \cdot 8}

2 0^{2} - 4 \cdot 8 \cdot 8 = 12

x_{1, 2} = \frac{- 20 \pm 12}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 20 + 12}{2 \cdot 8}, x_{2} = \frac{- 20 - 12}{2 \cdot 8}

x = \frac{- 20 + 12}{2 \cdot 8} : - \frac{1}{2}

x = \frac{- 20 - 12}{2 \cdot 8} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 2

\frac{1}{5} + \frac{1}{20}

(y - 9) (y + 8) = 0

\frac{2}{3} (x + 7) = 6

\frac{- 12 + - 18}{60}

lo g_{2} (\frac{1}{4})

What are the solutions to the equation 8x^2+20x+8=0 ?
The solutions to the equation 8x^2+20x+8=0 are x=-1/2 ,x=-2
Find the zeros of 8x^2+20x+8=0
The zeros of 8x^2+20x+8=0 are x=-1/2 ,x=-2