What is (3-2x)/((x+2)(7-x))<= 0 ?

The solution to (3-2x)/((x+2)(7-x))<= 0 is x<-2\lor 3/2 <= x<7

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(3-2x)/((x+2)(7-x))<= 0

\frac{3 - 2 x}{( x + 2 ) ( 7 - x )} \leq 0

x < - 2 or \frac{3}{2} \leq x < 7

Interval Notation

(- \infty, - 2) \cup [\frac{3}{2}, 7)

Decimal Notation

x < - 2 or 1.5 \leq x < 7

Solution steps

\frac{3 - 2 x}{( x + 2 ) ( 7 - x )} \leq 0

Identify the intervals

x < - 2 or \frac{3}{2} \leq x < 7

(\frac{1}{16})^{- \frac{5}{4}}

3 (x - 1) = - 12

5 x^{2} + 30 x + 45

\frac{3}{4} x^{- \frac{1}{4}}

(2 x y) (- 4 x^{2}) + (6 x) (6 x^{2} y)

What is (3-2x)/((x+2)(7-x))<= 0 ?
The solution to (3-2x)/((x+2)(7-x))<= 0 is x<-2\lor 3/2 <= x<7