What are the solutions to the equation 9^2+b^2=11^2 ?

The solutions to the equation 9^2+b^2=11^2 are b=2sqrt(10),b=-2sqrt(10)

Find the zeros of 9^2+b^2=11^2

The zeros of 9^2+b^2=11^2 are b=2sqrt(10),b=-2sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{2} + b^{2} = 1 1^{2}

b = 210, b = - 210

Decimal Notation

b = 6.32455 \dots, b = - 6.32455 \dots

Solution steps

9^{2} + b^{2} = 1 1^{2}

Move

9^{2}

to the right side

b^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 40, b = - 40

40 = 210

- 40 = - 210

b = 210, b = - 210

x^{5} - x

x - 5 \cdot x + 2

(64 n^{9})^{\frac{2}{3}}

12 + 2 x - x = 9 x + 6

(27 x^{6} y^{9})^{\frac{2}{3}}

What are the solutions to the equation 9^2+b^2=11^2 ?
The solutions to the equation 9^2+b^2=11^2 are b=2sqrt(10),b=-2sqrt(10)
Find the zeros of 9^2+b^2=11^2
The zeros of 9^2+b^2=11^2 are b=2sqrt(10),b=-2sqrt(10)