What are the solutions to the equation 3x^2-x=4 ?

The solutions to the equation 3x^2-x=4 are x= 4/3 ,x=-1

Find the zeros of 3x^2-x=4

The zeros of 3x^2-x=4 are x= 4/3 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - x = 4

x = \frac{4}{3}, x = - 1

Decimal Notation

x = 1.33333 \dots, x = - 1

Solution steps

3 x^{2} - x = 4

Move

4

to the left side

3 x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 4) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 3}

x = \frac{- ( - 1 ) + 7}{2 \cdot 3} : \frac{4}{3}

x = \frac{- ( - 1 ) - 7}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 1

8^{- 2}

15 x^{2} - 6 = x

7 (x - 3) + 3 (4 - x) = - 8

1 < ∣ x ∣ < 2

\frac{1}{3} π

What are the solutions to the equation 3x^2-x=4 ?
The solutions to the equation 3x^2-x=4 are x= 4/3 ,x=-1
Find the zeros of 3x^2-x=4
The zeros of 3x^2-x=4 are x= 4/3 ,x=-1