What is 3sqrt(x)-4>= 5 ?

The solution to 3sqrt(x)-4>= 5 is x>= 9

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3sqrt(x)-4>= 5

3 x - 4 \geq 5

x \geq 9

Interval Notation

Solution steps

3 x - 4 \geq 5

Move

4

to the right side

3 x \geq 9

Divide both sides by

3

x \geq 3

Square both sides

(x)^{2} \geq 3^{2}

Simplify

x \geq 9

Find singularity points

Find non-negative values for radicals:

x \geq 0

Combine the intervals

x \geq 9 and x \geq 0

Merge Overlapping Intervals

x \geq 9

8 \cdot 5

\frac{( 4 p ^{- 4} q ) ^{- 2}}{10 p q ^{- 3}}

7 x - 8 < 4 x + 7

\frac{x}{6} = \frac{1}{12} + \frac{x}{8}

\frac{x ^{2} + 4 x + 3}{x - 1} > 0