What is (0.3(x+2000)+0.06x)-0.34(x+2000)>= 1000 ?

The solution to (0.3(x+2000)+0.06x)-0.34(x+2000)>= 1000 is x>= 54000

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(0.3(x+2000)+0.06x)-0.34(x+2000)>= 1000

(0.3 (x + 2000) + 0.06 x) - 0.34 (x + 2000) \geq 1000

x \geq 54000

Interval Notation

[54000, \infty)

Solution steps

(0.3 (x + 2000) + 0.06 x) - 0.34 (x + 2000) \geq 1000

Remove parentheses:

(a) = a

0.3 (x + 2000) + 0.06 x - 0.34 (x + 2000) \geq 1000

Add similar elements:

0.3 (x + 2000) - 0.34 (x + 2000) = - 0.04 (x + 2000)

- 0.04 (x + 2000) + 0.06 x \geq 1000

Multiply both sides by

100

- 4 (x + 2000) + 6 x \geq 100000

Expand

- 4 (x + 2000) + 6 x : 2 x - 8000

2 x - 8000 \geq 100000

Move

8000

to the right side

2 x \geq 108000

Divide both sides by

2

x \geq 54000

\frac{1}{\frac{3}{4}}

\frac{4 ^{2}}{4 ^{7}}

- 2 = 0

\frac{x ^{2} ( 8 + x ) ( x - 5 )}{( x + 6 ) ( x - 2 )} \geq 0

3 lo g_{3} (3)

What is (0.3(x+2000)+0.06x)-0.34(x+2000)>= 1000 ?
The solution to (0.3(x+2000)+0.06x)-0.34(x+2000)>= 1000 is x>= 54000