What are the solutions to the equation -8x^2+7=4 ?

The solutions to the equation -8x^2+7=4 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

Find the zeros of -8x^2+7=4

The zeros of -8x^2+7=4 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

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Popular >

- 8 x^{2} + 7 = 4

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

Decimal

x = 0.61237 \dots, x = - 0.61237 \dots

Solution steps

- 8 x^{2} + 7 = 4

Move

7

to the right side

- 8 x^{2} = - 3

Divide both sides by

- 8

x^{2} = \frac{3}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{8}, x = - \frac{3}{8}

\frac{3}{8} = \frac{3}{2 2}

- \frac{3}{8} = - \frac{3}{2 2}

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

15 x + 15 < 3 (5 x + 20)

\frac{4}{3} \cdot 27

3^{- 0.5}

4225

(- 6 x^{3} y)^{4}

What are the solutions to the equation -8x^2+7=4 ?
The solutions to the equation -8x^2+7=4 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))
Find the zeros of -8x^2+7=4
The zeros of -8x^2+7=4 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))