What are the solutions to the equation 3u^2-5=14u ?

The solutions to the equation 3u^2-5=14u are u=5,u=-1/3

Find the zeros of 3u^2-5=14u

The zeros of 3u^2-5=14u are u=5,u=-1/3

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3 u^{2} - 5 = 14 u

u = 5, u = - \frac{1}{3}

Solution steps

3 u^{2} - 5 = 14 u

Move

14 u

to the left side

3 u^{2} - 5 - 14 u = 0

Write in the standard form

a x^{2} + b x + c = 0

3 u^{2} - 14 u - 5 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 (- 5) = 16

u_{1, 2} = \frac{- ( - 14 ) \pm 16}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- ( - 14 ) + 16}{2 \cdot 3}, u_{2} = \frac{- ( - 14 ) - 16}{2 \cdot 3}

u = \frac{- ( - 14 ) + 16}{2 \cdot 3} : 5

u = \frac{- ( - 14 ) - 16}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

u = 5, u = - \frac{1}{3}

\frac{11 π}{6} - 4 π

\frac{x - 2}{3 x + 5} \leq 4

- \frac{1}{2} + 2

1 - e^{- \frac{π}{4} (\frac{5}{10})^{2}}

What are the solutions to the equation 3u^2-5=14u ?
The solutions to the equation 3u^2-5=14u are u=5,u=-1/3
Find the zeros of 3u^2-5=14u
The zeros of 3u^2-5=14u are u=5,u=-1/3