What is ((-8x^4y^{-2})/(3z^2))^{-1} ?

The solution to ((-8x^4y^{-2})/(3z^2))^{-1} is -(3y^2z^2)/(8x^4)

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simplify ((-8x^4y^{-2})/(3z^2))^{-1}

simplify

(\frac{- 8 x ^{4} y ^{- 2}}{3 z ^{2}})^{- 1}

- \frac{3 y ^{2} z ^{2}}{8 x ^{4}}

Solution steps

(\frac{- 8 x ^{4} y ^{- 2}}{3 z ^{2}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{- 8 x ^{4} y ^{- 2}}{3 z ^{2}})^{- 1} = \frac{1}{\frac{- 8 x ^{4} y ^{- 2}}{3 z ^{2}}}

= \frac{1}{\frac{- 8 x ^{4} y ^{- 2}}{3 z ^{2}}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= \frac{1}{- \frac{8 x ^{4} y ^{- 2}}{3 z ^{2}}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1}{\frac{8 x ^{4} y ^{- 2}}{3 z ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

\frac{1}{\frac{8 x ^{4} y ^{- 2}}{3 z ^{2}}} = \frac{3 z ^{2}}{8 x ^{4} y ^{- 2}}

= - \frac{3 z ^{2}}{8 x ^{4} y ^{- 2}}

y^{- 2} = \frac{1}{y ^{2}}

= - \frac{3 z ^{2}}{8 \cdot \frac{1}{y ^{2}} x ^{4}}

Multiply

8 x^{4} \frac{1}{y ^{2}} : \frac{8 x ^{4}}{y ^{2}}

= - \frac{3 z ^{2}}{\frac{8 x ^{4}}{y ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= - \frac{3 y ^{2} z ^{2}}{8 x ^{4}}

- 4 (x - 1) \leq 40

x^{21}

\frac{2}{4} - \frac{1}{5}

x < - 1 and x < 1

- 13 m = - 377

What is ((-8x^4y^{-2})/(3z^2))^{-1} ?
The solution to ((-8x^4y^{-2})/(3z^2))^{-1} is -(3y^2z^2)/(8x^4)