What are the solutions to the equation 11a^2-7a-21=-6 ?

The solutions to the equation 11a^2-7a-21=-6 are a=(7+sqrt(709))/(22),a=(7-sqrt(709))/(22)

Find the zeros of 11a^2-7a-21=-6

The zeros of 11a^2-7a-21=-6 are a=(7+sqrt(709))/(22),a=(7-sqrt(709))/(22)

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11 a^{2} - 7 a - 21 = - 6

a = \frac{7 + 709}{22}, a = \frac{7 - 709}{22}

Decimal Notation

a = 1.52850 \dots, a = - 0.89213 \dots

Solution steps

11 a^{2} - 7 a - 21 = - 6

Move

6

to the left side

11 a^{2} - 7 a - 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 11 ( - 15 )}{2 \cdot 11}

(- 7)^{2} - 4 \cdot 11 (- 15) = 709

a_{1, 2} = \frac{- ( - 7 ) \pm 709}{2 \cdot 11}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 709}{2 \cdot 11}, a_{2} = \frac{- ( - 7 ) - 709}{2 \cdot 11}

a = \frac{- ( - 7 ) + 709}{2 \cdot 11} : \frac{7 + 709}{22}

a = \frac{- ( - 7 ) - 709}{2 \cdot 11} : \frac{7 - 709}{22}

The solutions to the quadratic equation are:

a = \frac{7 + 709}{22}, a = \frac{7 - 709}{22}

\frac{6 x + 2}{x - 1} = 3

\frac{3}{8} x + 2 - \frac{4}{5} x = 1 + \frac{3}{10} x + \frac{3}{2}

\frac{5 !}{( 5 - 3 ) !}

4 x^{3} - 6 x^{2} + 2 x

What are the solutions to the equation 11a^2-7a-21=-6 ?
The solutions to the equation 11a^2-7a-21=-6 are a=(7+sqrt(709))/(22),a=(7-sqrt(709))/(22)
Find the zeros of 11a^2-7a-21=-6
The zeros of 11a^2-7a-21=-6 are a=(7+sqrt(709))/(22),a=(7-sqrt(709))/(22)