What is factor 2(x^3-1)-3(x^2-1) ?

The solution to factor 2(x^3-1)-3(x^2-1) is (x-1)^2(2x+1)

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factor 2(x^3-1)-3(x^2-1)

factor

2 (x^{3} - 1) - 3 (x^{2} - 1)

(x - 1)^{2} (2 x + 1)

Solution steps

2 (x^{3} - 1) - 3 (x^{2} - 1)

Factor

x^{3} - 1 : (x - 1) (x^{2} + x + 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= 2 (x - 1) (x^{2} + x + 1) - 3 (x + 1) (x - 1)

Factor out common term

x - 1

= (x - 1) (2 (x^{2} + x + 1) - 3 (x + 1))

Expand

2 (x^{2} + x + 1) - 3 (x + 1) : 2 x^{2} - x - 1

= (x - 1) (2 x^{2} - x - 1)

Factor

2 x^{2} - x - 1 : (2 x + 1) (x - 1)

= (x - 1) (2 x + 1) (x - 1)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (2 x + 1)

\frac{x - 6}{x - 1} \geq 0

t - 8 = 14

f = 3 (5) + 2

\frac{x + 1}{3} = - 2

x^{5} - x^{4} - x^{3} - x^{2} - 2 x \leq 0

What is factor 2(x^3-1)-3(x^2-1) ?
The solution to factor 2(x^3-1)-3(x^2-1) is (x-1)^2(2x+1)