What are the solutions to the equation 8x^2+3x-5=0 ?

The solutions to the equation 8x^2+3x-5=0 are x= 5/8 ,x=-1

Find the zeros of 8x^2+3x-5=0

The zeros of 8x^2+3x-5=0 are x= 5/8 ,x=-1

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8 x^{2} + 3 x - 5 = 0

x = \frac{5}{8}, x = - 1

Decimal Notation

x = 0.625, x = - 1

Solution steps

8 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

3^{2} - 4 \cdot 8 (- 5) = 13

x_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 3 + 13}{2 \cdot 8}, x_{2} = \frac{- 3 - 13}{2 \cdot 8}

x = \frac{- 3 + 13}{2 \cdot 8} : \frac{5}{8}

x = \frac{- 3 - 13}{2 \cdot 8} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{8}, x = - 1

(\frac{1}{2})^{- 2}

2 x - ∣ x + 3 ∣ = 9

\frac{π}{4} - 1

12 8^{\frac{5}{4}} \cdot 2^{\frac{5}{4}}

- 1 - (- 2)

What are the solutions to the equation 8x^2+3x-5=0 ?
The solutions to the equation 8x^2+3x-5=0 are x= 5/8 ,x=-1
Find the zeros of 8x^2+3x-5=0
The zeros of 8x^2+3x-5=0 are x= 5/8 ,x=-1