What are the solutions to the equation x^2-10x+9=0 ?

The solutions to the equation x^2-10x+9=0 are x=9,x=1

Find the zeros of x^2-10x+9=0

The zeros of x^2-10x+9=0 are x=9,x=1

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x^{2} - 10 x + 9 = 0

x = 9, x = 1

Solution steps

x^{2} - 10 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 9 = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 1}

x = \frac{- ( - 10 ) + 8}{2 \cdot 1} : 9

x = \frac{- ( - 10 ) - 8}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 9, x = 1

33 + 6 + 12 - 23

- 6 x + 9 = 25

\frac{x ^{3} y z ^{3}}{( x y z ^{- 1} ) ^{- 1}}

4 - 10

- 1.5 (x - 3) = 4

What are the solutions to the equation x^2-10x+9=0 ?
The solutions to the equation x^2-10x+9=0 are x=9,x=1
Find the zeros of x^2-10x+9=0
The zeros of x^2-10x+9=0 are x=9,x=1