What is (3x^{-3}y^3)/(9x^4(y^{-3))^4} ?

The solution to (3x^{-3}y^3)/(9x^4(y^{-3))^4} is (y^{15})/(3x^7)

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simplify (3x^{-3}y^3)/(9x^4(y^{-3))^4}

simplify

\frac{3 x ^{- 3} y ^{3}}{9 x ^{4} ( y ^{- 3} ) ^{4}}

\frac{y ^{15}}{3 x ^{7}}

Solution steps

\frac{3 x ^{- 3} y ^{3}}{9 x ^{4} ( y ^{- 3} ) ^{4}}

Simplify

(y^{- 3})^{4} : \frac{1}{y ^{12}}

= \frac{3 x ^{- 3} y ^{3}}{9 x ^{4} \frac{1}{y ^{12}}}

Factor the number:

9 = 3 \cdot 3

= \frac{3 x ^{- 3} y ^{3}}{3 \cdot 3 x ^{4} \frac{1}{y ^{12}}}

Cancel the common factor:

3

= \frac{x ^{- 3} y ^{3}}{3 x ^{4} \frac{1}{y ^{12}}}

Simplify

\frac{x ^{- 3}}{x ^{4}} : \frac{1}{x ^{7}}

= \frac{y ^{3}}{3 x ^{7} \frac{1}{y ^{12}}}

Simplify

\frac{y ^{3}}{3 x ^{7} \frac{1}{y ^{12}}} : \frac{y ^{15}}{3 x ^{7}}

= \frac{y ^{15}}{3 x ^{7}}

∣ x + 1 ∣ < 5

b (a + 1)^{2} - 5 \cdot (a + 1)

5 (x + 2) = 3 x

- 5 - 3 w = 7 w

x = 2^{- 2}

What is (3x^{-3}y^3)/(9x^4(y^{-3))^4} ?
The solution to (3x^{-3}y^3)/(9x^4(y^{-3))^4} is (y^{15})/(3x^7)