What is (3^{-2}a^0)/(b^{-2)} ?

The solution to (3^{-2}a^0)/(b^{-2)} is (b^2)/9

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simplify (3^{-2}a^0)/(b^{-2)}

simplify

\frac{3 ^{- 2} a ^{0}}{b ^{- 2}}

\frac{b ^{2}}{9}

Solution steps

\frac{3 ^{- 2} a ^{0}}{b ^{- 2}}

Simplify

3^{- 2} a^{0} : \frac{1}{9}

= \frac{\frac{1}{9}}{b ^{- 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{9 b ^{- 2}}

Simplify

9 b^{- 2} : \frac{9}{b ^{2}}

= \frac{1}{\frac{9}{b ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{2}}{9}

x + 4 \geq \frac{1}{2} (x - 3)

\frac{n}{n + 1} - 1

3 x \leq 20 - 2 x^{2}

19 - ∣ 2 m + 23 ∣ = 39

\frac{4}{3 + 2}