What are the solutions to the equation 6x+2x=48xx ?

The solutions to the equation 6x+2x=48xx are x= 1/6 ,x=0

Find the zeros of 6x+2x=48xx

The zeros of 6x+2x=48xx are x= 1/6 ,x=0

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6 x + 2 x = 48 xx

x = \frac{1}{6}, x = 0

Decimal Notation

x = 0.16666 \dots, x = 0

Solution steps

6 x + 2 x = 48 xx

Expand

48 xx : 48 x^{2}

8 x = 48 x^{2}

Switch sides

48 x^{2} = 8 x

Move

8 x

to the left side

48 x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 48 \cdot 0}{2 \cdot 48}

(- 8)^{2} - 4 \cdot 48 \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 \cdot 48}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 \cdot 48}, x_{2} = \frac{- ( - 8 ) - 8}{2 \cdot 48}

x = \frac{- ( - 8 ) + 8}{2 \cdot 48} : \frac{1}{6}

x = \frac{- ( - 8 ) - 8}{2 \cdot 48} : 0

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = 0

- \frac{4}{8}

- 16 x + 64

12 x^{2} - 6 x - 18

82 + 4

\frac{- 4 x + 20}{- 5}

What are the solutions to the equation 6x+2x=48xx ?
The solutions to the equation 6x+2x=48xx are x= 1/6 ,x=0
Find the zeros of 6x+2x=48xx
The zeros of 6x+2x=48xx are x= 1/6 ,x=0