What are the solutions to the equation 2pir^2+6pir=8pi ?

The solutions to the equation 2pir^2+6pir=8pi are r=1,r=-4

Find the zeros of 2pir^2+6pir=8pi

The zeros of 2pir^2+6pir=8pi are r=1,r=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 π r^{2} + 6 π r = 8 π

r = 1, r = - 4

Solution steps

2 π r^{2} + 6 π r = 8 π

Move

8 π

to the left side

2 π r^{2} + 6 π r - 8 π = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 π \pm ( 6 π ) ^{2} - 4 \cdot 2 π ( - 8 π )}{2 \cdot 2 π}

(6 π)^{2} - 4 \cdot 2 π (- 8 π) = 10 π

r_{1, 2} = \frac{- 6 π \pm 10 π}{2 \cdot 2 π}

Separate the solutions

r_{1} = \frac{- 6 π + 10 π}{2 \cdot 2 π}, r_{2} = \frac{- 6 π - 10 π}{2 \cdot 2 π}

r = \frac{- 6 π + 10 π}{2 \cdot 2 π} : 1

r = \frac{- 6 π - 10 π}{2 \cdot 2 π} : - 4

The solutions to the quadratic equation are:

r = 1, r = - 4

x^{3} - 4 x^{2} + 5 x - 2

x^{2} - 2 x - 8 > 0

x^{4} + x^{3} - 16 x^{2} + 20 x

752 = 234 + 197 + x

- x > - 1

What are the solutions to the equation 2pir^2+6pir=8pi ?
The solutions to the equation 2pir^2+6pir=8pi are r=1,r=-4
Find the zeros of 2pir^2+6pir=8pi
The zeros of 2pir^2+6pir=8pi are r=1,r=-4