What is factor 1+27y^3 ?

The solution to factor 1+27y^3 is (3y+1)(9y^2-3y+1)

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factor 1+27y^3

factor

1 + 27 y^{3}

(3 y + 1) (9 y^{2} - 3 y + 1)

Solution steps

1 + 27 y^{3}

Write in the standard form

= 27 y^{3} + 1

Apply exponent rules

= (3 y)^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 y)^{3} + 1^{3} = (3 y + 1) (3^{2} y^{2} - 3 y + 1)

= (3 y + 1) (3^{2} y^{2} - 3 y + 1)

3^{2} = 9

= (3 y + 1) (9 y^{2} - 3 y + 1)

\frac{1}{2} + \frac{π}{2}

\frac{\frac{3}{3}}{\frac{5 π}{6}}

- 10 x y^{5} z^{4} + 33 y z^{3}

2 v^{2} + 7 v + 5