What is 1-x-2x^2>= 0 ?

The solution to 1-x-2x^2>= 0 is -1<= x<= 1/2

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1-x-2x^2>= 0

1 - x - 2 x^{2} \geq 0

- 1 \leq x \leq \frac{1}{2}

Interval Notation

[- 1, \frac{1}{2}]

Decimal Notation

- 1 \leq x \leq 0.5

Solution steps

1 - x - 2 x^{2} \geq 0

Factor

1 - x - 2 x^{2} : - (2 x - 1) (x + 1)

- (2 x - 1) (x + 1) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (2 x - 1) (x + 1)) (- 1) \leq 0 \cdot (- 1)

Simplify

(2 x - 1) (x + 1) \leq 0

Identify the intervals

- 1 \leq x \leq \frac{1}{2}

- 43 z \geq 3

(n^{\frac{1}{3}})^{\frac{3}{2}}

22 5^{2}

(64)^{\frac{1}{6}}

3 \cdot 36