What are the solutions to the equation 4=(x+5)^2 ?

The solutions to the equation 4=(x+5)^2 are x=-3,x=-7

Find the zeros of 4=(x+5)^2

The zeros of 4=(x+5)^2 are x=-3,x=-7

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4 = (x + 5)^{2}

x = - 3, x = - 7

Solution steps

4 = (x + 5)^{2}

Switch sides

(x + 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 4 : x = - 3

Solve

x + 5 = - 4 : x = - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

5 x^{2} - 18 x - 8

- 7 \leq 4 x + 27 < 33

4 n + 7 > 43

\frac{( 6 x + 9 ) ( 6 x - 4 )}{6}

\frac{144}{36}

What are the solutions to the equation 4=(x+5)^2 ?
The solutions to the equation 4=(x+5)^2 are x=-3,x=-7
Find the zeros of 4=(x+5)^2
The zeros of 4=(x+5)^2 are x=-3,x=-7