What are the solutions to the equation (2x+9)^2-72=0 ?

The solutions to the equation (2x+9)^2-72=0 are x=(6sqrt(2)-9)/2 ,x=(-6sqrt(2)-9)/2

Find the zeros of (2x+9)^2-72=0

The zeros of (2x+9)^2-72=0 are x=(6sqrt(2)-9)/2 ,x=(-6sqrt(2)-9)/2

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(2 x + 9)^{2} - 72 = 0

x = \frac{6 2 - 9}{2}, x = \frac{- 6 2 - 9}{2}

Decimal Notation

x = - 0.25735 \dots, x = - 8.74264 \dots

Solution steps

(2 x + 9)^{2} - 72 = 0

Move

72

to the right side

(2 x + 9)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 9 = 72 : x = \frac{6 2 - 9}{2}

Solve

2 x + 9 = - 72 : x = \frac{- 6 2 - 9}{2}

The solutions to the quadratic equation are:

x = \frac{6 2 - 9}{2}, x = \frac{- 6 2 - 9}{2}

\frac{7}{6} - \frac{9}{2} + \frac{11}{3} - \frac{5}{12}

5 x - 15 = 2 x + 21

x^{3} - 7 x^{2} + 11 x + 3

- \frac{5 π}{4} - 2 π

(3 x^{2} y - 2 x + 1) + (4 x^{2} y + 6 x - 3)

What are the solutions to the equation (2x+9)^2-72=0 ?
The solutions to the equation (2x+9)^2-72=0 are x=(6sqrt(2)-9)/2 ,x=(-6sqrt(2)-9)/2
Find the zeros of (2x+9)^2-72=0
The zeros of (2x+9)^2-72=0 are x=(6sqrt(2)-9)/2 ,x=(-6sqrt(2)-9)/2