What are the solutions to the equation 2x^2-9x-8=0 ?

The solutions to the equation 2x^2-9x-8=0 are x=(9+sqrt(145))/4 ,x=(9-sqrt(145))/4

Find the zeros of 2x^2-9x-8=0

The zeros of 2x^2-9x-8=0 are x=(9+sqrt(145))/4 ,x=(9-sqrt(145))/4

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2 x^{2} - 9 x - 8 = 0

x = \frac{9 + 145}{4}, x = \frac{9 - 145}{4}

Decimal Notation

x = 5.26039 \dots, x = - 0.76039 \dots

Solution steps

2 x^{2} - 9 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 8) = 145

x_{1, 2} = \frac{- ( - 9 ) \pm 145}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 145}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 145}{2 \cdot 2}

x = \frac{- ( - 9 ) + 145}{2 \cdot 2} : \frac{9 + 145}{4}

x = \frac{- ( - 9 ) - 145}{2 \cdot 2} : \frac{9 - 145}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 145}{4}, x = \frac{9 - 145}{4}

- 2 k > 18

(x - 3)^{2} = 81

- 243

4 b^{2} - 8 b - 1 = 0

lo g_{2} (12) - 2 lo g_{2} (x)

What are the solutions to the equation 2x^2-9x-8=0 ?
The solutions to the equation 2x^2-9x-8=0 are x=(9+sqrt(145))/4 ,x=(9-sqrt(145))/4
Find the zeros of 2x^2-9x-8=0
The zeros of 2x^2-9x-8=0 are x=(9+sqrt(145))/4 ,x=(9-sqrt(145))/4